asked 225k views
0 votes
A 59g particle is moving to the left at 27 m/s . How much net work must be done on the particle to cause it to move to the right at 38 m/s?

asked
User Ashtav
by
8.4k points

1 Answer

4 votes

Step-by-step explanation:

To find the net work done on the particle to cause it to move to the right at 38 m/s, we need to use the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy:

Net work = ΔK = 1/2 * m * (vf^2 - vi^2)

where m is the mass of the particle, vi is its initial velocity (to the left), and vf is its final velocity (to the right).

Substituting the given values, we get:

Net work = 1/2 * 0.059 kg * (38 m/s)^2 - 1/2 * 0.059 kg * (27 m/s)^2

Net work = 46.4657 J - 22.6545 J

Net work = 23.8112 J

Therefore, the net work done on the particle to cause it to move to the right at 38 m/s is 23.8112 Joules.

answered
User Cubiclewar
by
8.7k points