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In a right triangle, a and b are the lengths of the legs and c is the length of the hypotenuse. If A = 68 kilometers and B =51 kilometers, what is c? If necessary, round to the nearest tenth.​

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User Gimnath
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\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2\implies c=√(a^2 + o^2) \end{array} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{68}\\ o=\stackrel{opposite}{51} \end{cases} \\\\\\ c=√( 68^2 + 51^2)\implies c=√( 4624 + 2601 ) \implies c=√( 7225 ) \implies c=85

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User Prmph
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