Question

Write the equation of a line PERPENDICULAR

to 3x + y = 1 that passes through the point (3,
-1).

Answer 1

im pretty sure its y=1/3x

Explanation:

rearrange for y to be subject

its perpendicular so then the gradient will be the negative reciprocal (-1 / -3= 1/3) so thats your new gradient

then when you substitute the (3,-1) into that equation get -1=1 + c so then c is 0 and your whole equation is y=1/3x