Question

A bag contains 7 marbles: one each of red, orange, yellow, green, blue, violet, and white. A child randomly pulls 4 marbles from the bag. What is the probability that the marbles chosen are green, blue, red, and yellow? round

Answer 1

`(1)/(35)=0.029`

Explanation:

Each marble has a probability
`(1)/(7)` of being pulled out of the bag.

We need to pull out green, blue, red or yellow in the first pull.

That is mean we have a
`(4)/(7)` probability to choose one of these. (Let it be green marble)

In secend pull we have 6 marbles in the bag and 3 of them we need to pull out. That is meean we have a probability
`(3)/(6)` to choose one of these (Let it be blue marble).

In third pull we have 5 marbles in the bag and 2 of them we need to pull out. That is meean we have a probability
`(2)/(5)` to choose one of these (Let it be red marble).

In last pull we have 4 marbles in the bag and we need to pull out last one (yellow). That is meean we have a probability
`(1)/(4)`.

`(4)/(7) *(3)/(6) *(2)/(5)* (1)/(4) =(4)/(7) *(1)/(2) *(2)/(5) *(1)/(4) =(1)/(35)= 0.029`