Question

Gas is contained in a vertical, frictionless piston–cylinder device. The piston has a mass of 4 kg and a cross-sectional area of 35 cm2. A compressed spring above the piston exerts a force of 60 N on the piston. If the atmospheric pressure is 95 kPa, determine the pressure inside the cylinder.

Answer 1

Answer:135.397 Kpa

Step-by-step explanation:

Given : mass of piston = 4 kg

cross-sectional area = 35

exert force of piston is = 60 N.

p = 95 kPa

To find atmospheric pressure inside the cylinder

total force acting on the piston = spring force + piston self weight

pressure due to Forces

Pgauge=W/A+F/A

Mag/A+F/A

3.2*9.82/35*10^5+110/35*10^5

8969.14331428.571

Pgauge=4039.714=40.398KPa

Hence total pressure inside the cylinder

=Patm+Pgauge

= 95+40.398

= 135.397 Kpa