Find length of side of Rhombous whose diagonals are 6cm and 12cm

Question

asked Nov 12, 2024 100k views

2 Answers

Drmuelr · Answer 1 · 2024-11-14T02:21:44+0000

Explanation:

We know that diagonals of a rhombus perpendicularly bisect each other.

Therefore

Let side of rhombus be 'a' , then

${a}^(2) =( (d1)/(2) )^(2) + ( (d2)/(2) ) + = (12)/(2)^(2) + ( (6)/(2)) ^(2) = 36 + 9 \\ \\ a ^(2) = 45 = a = \sqrt[3]{5}$