Question

A motor moves a belt that is attach to an axle of a solid flywheel. The radius of the axle r = 3.25 cm and the radius of the larger solid flywheel is R = 27.4 cm. What is the tangential velocity of the outer edge of the fly wheel assuming the belt has linear velocity of 45.0 m/s?​

Answer 1

Step-by-step explanation:

We can start by using the fact that the linear velocity of the belt is equal to the tangential velocity of the flywheel at the point where the belt contacts it. We can use this to find the tangential velocity of the outer edge of the flywheel using the ratio of the radii.

Let's call the tangential velocity of the outer edge of the flywheel "v". Then we have:

v / 45.0 m/s = R / r

where R is the radius of the flywheel and r is the radius of the axle. We can rearrange this to solve for v:

v = (45.0 m/s) * (R / r)

Substituting in the given values for R and r, we get:

v = (45.0 m/s) * (27.4 cm / 3.25 cm)

Converting the radius to meters:

v = (45.0 m/s) * (0.274 m / 0.0325 m)

Simplifying:

v = 379.6 m/s

Therefore, the tangential velocity of the outer edge of the flywheel is approximately 379.6 m/s