Question

PLEASE HELP ME DUE MIDNIGHT !!!

Answer 1

Column 1:

`\pi/3` (given)

`5\pi/4`

`11\pi/6`

Column 2:

`√(3)/2`

`-√(2)/2` (given)

`-1/2`

Column 3:

all given

Column 4:

`√(3)`

`1`

`-√(3)/3` (given)

Explanation:

Solved by using unit circle and inverse trig functions