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At how many points does the line with equation y = -3/4x + 25/4 intersect the circle shown?

A. 0

B. 1

C. 2

D. There is not enough information to determine the number of points of intersection.

At how many points does the line with equation y = -3/4x + 25/4 intersect the circle-example-1
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User Zkunov
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Answer:

We need to find the number of points of intersection between the line with equation y = -3/4x + 25/4 and the circle. The equation of the circle is not given, so we cannot directly solve for the intersection points. However, we can use the fact that the intersection points must satisfy both the equation of the line and the equation of the circle.

Let (x, y) be a point on the circle. Then the coordinates satisfy the equation of the circle, which we will assume is (x - a)^2 + (y - b)^2 = r^2, where (a, b) is the center of the circle and r is the radius. Substituting y = -3/4x + 25/4, we get:

(x - a)^2 + (-3/4x + 25/4 - b)^2 = r^2

This is a quadratic equation in x, which we can expand and simplify:

(x^2 - 2ax + a^2) + (-3/2)x^2 + (15/2)x - 3bx + (625/16) + b^2 - (25/2)b + (625/16) - r^2 = 0

Simplifying further, we get:

(-5/2)x^2 + (-2a - 3b + 15/2)x + (2a^2 - 25/2b + 125/8 - r^2) = 0

This is a quadratic equation in x, with coefficients that depend on the center and radius of the circle. We can use the quadratic formula to solve for x, and then substitute into y = -3/4x + 25/4 to get the corresponding value of y.

The discriminant of the quadratic equation is:

(-2a - 3b + 15/2)^2 - 4(-5/2)(2a^2 - 25/2b + 125/8 - r^2)

Simplifying and factoring, we get:

(4a + 6b - 15)^2 - 25(4a^2 - 50b + 250/8 - 2r^2)

This is a quadratic expression in b, which tells us whether the equation has real solutions (i.e., whether the line intersects the circle). If the discriminant is positive, then the equation has two real solutions, which means the line intersects the circle at two points. If the discriminant is zero, then the equation has one real solution, which means the line is tangent to the circle. If the discriminant is negative, then the equation has no real solutions, which means the line does not intersect the circle.

Without knowing the equation of the circle, we cannot determine the discriminant and therefore the number of intersection points. Therefore, the answer is D: "There is not enough information to determine the number of points of intersection."

Explanation:

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User Andru Luvisi
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