Answer:
Let's assume that the width of the rectangle is 'w' meters.
According to the problem, the length of the rectangle is three times its width, so the length is:
l = 3w
The area of the rectangle is given as 300 m², so we have:
lw = 300
Substituting the value of 'l' in terms of 'w', we get:
(3w)w = 300
Simplifying the above equation, we get:
3w^2 = 300
Dividing both sides by 3, we get:
w^2 = 100
Taking the square root on both sides, we get:
w = 10
So the width of the rectangle is 10 meters.
Using the value of 'w', we can find the length of the rectangle:
l = 3w = 3(10) = 30
So the length of the rectangle is 30 meters.
The perimeter of the rectangle is given by:
P = 2(l + w)
Substituting the values of 'l' and 'w', we get:
P = 2(30 + 10) = 2(40) = 80
Therefore, the perimeter of the rectangle is 80 meters.
Explanation: