Question

You wrote a program to determine if a password contained a numeric character.

password = input("Password? ")
hasNumber = False
for character in password:
if character.isdigit():
hasNumber = True
break

Finish the code that is a shorter alternate.

password = input("Password? ")
valid = True
if not __ (character.isdigit() for character in password)
valid = False

Answer 1

Here is the completed code that is a shorter alternate to the given program:

`\rm \: valid = not \: all(character.isalpha() for \: character \: in \: password)`

This code uses a generator expression within the all() function to check if all characters in the password are alphabetical. If all characters are alphabetical, the expression evaluates to True, and the not operator negates it to False, indicating that the password is not valid. If at least one character is a digit, the expression evaluates to 'False', and the 'not' operator negates it to 'True', indicating that the password is valid.

The variable valid is assigned the resulting Boolean value indicating if the password is valid or 'not'

Answer 2

any

Step-by-step explanation:

"any" bc i got it right