Question

A car approaches a stop sign going 5 m/s before it comes to a stop. If it does this in 4 seconds, what was its acceleration?

Answer 1

`a = - (5)/(4) \: m{s}^( - 2)`

Step-by-step explanation:

a = acceleration (m/s²)

v = final velocity (m/s) = 0

u = initial velocity (m/s) = 5

t = time (s) = 4

`a = (v - u)/(t) \\ a = ((0 - 5))/(4) \\ a = - (5)/(4)`