Question

How many grams of oxygen are there in a 50L gas cylinder at 21 degrees Celsius and a pressure of 15. 7atm

Answer 1

It's 1.0407 Kilograms of oxygen (O2) in that container

Step-by-step explanation:

according to ideal gas law:


`PV = nRT`

P: pressure, V: volume, n: moles, R: gas constant = 0.0821, T: temperature in Kelvin

Temperature in Kelvin = Temperature in Celsius + 273
Gas constant (R) is changed by changing pressure units (while using atm, R = 0.0821 atm•L/mol•K )

by substituting with given data:


`15.7 * 50 = n*0.0821*(21+273)`


`n = (50*15.7)/(0.0821 * 294) = 32.522 mol`

So, O2 mass (Molar mass of O2 = 32 g/mol) = 32.522 * 32 = 1040.709 grams = 1.0407 kilograms