Question

The length of a

rectangular poster is 5 more inches than two
times its width. The area of the poster is 33 square inches. Solve
for the dimensions (length and width) of the poster.

Answer 1

width is 3 inches, length is 11 inches.

Explanation:

Let l be the length and w be the width.

We have:

`l = 2w + 5`

`(2w + 5)(w) = 33`

`2 {w}^(2) + 5w = 33`

`2 {w}^(2) + 5w - 33 = 0`

`(w - 3)(2w + 11) = 0`

`w = 3`

`l = 2(3) + 5 = 11`