Question

Evaluate the expression ¼1x2y + 32) when x = 8, y = 3, and z = 5/3.

Answer 1

(1/4)(1x^2y + 32)

Substituting x = 8, y = 3, and z = 5/3:

(1/4)(1(8)^2(3) + 32) = (1/4)(192 + 32) = (1/4)(224) = 56

Therefore, the value of the expression is 56.