Question

You have 9 apples and 7 oranges in a basket. You take randomly 3

items from the basket. What is the probability that you selected 1 apple and 2 oranges?
Please write your answer as a decimal. Round your answer to three decimal places.

Answer 1

0.337 or about 33.7%

Explanation:

The number of ways to choose 1 apple out of 9 is:

C(9, 1) = 9! / (1! * (9 - 1)!) = 9

The number of ways to choose 2 oranges out of 7 is:

C(7, 2) = 7! / (2! * (7 - 2)!) = 21

So the total number of ways to choose 1 apple and 2 oranges is:

9 * 21 = 189

The total number of ways to choose 3 fruits out of 16 is:

C(16, 3) = 560

Therefore, the probability of selecting 1 apple and 2 oranges is:

189 / 560 ≈ 0.337 or about 33.7%