Question

the length of a rectangle is 2 m longer than the width. if the perimeter of the rectangle is 56 m find the length and width​

Answer 1

Let W = width of rectangle

Let W + 2 = length of rectangle = L

Perimeter = 2L + 2W

56 = 2L + 2W

since L = W + 2, we can substitute and solve

56 = 2(W + 2) + 2W

56 = 2W + 4 + 2W

56 = 4W + 4

52 = 4W

W = 13

the length 2 more than 13, which is 15

Area = L • W

= 15 • 13

= 195