Question

Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $2,600 was collected on the sale of 1,160 tickets. How many of each type of ticket were sold?

Answer 1

360 adult tickets and 800 student tickets were sold.

Explanation:

Let's use a system of equations to solve this problem.

Let x be the number of adult tickets sold, and y be the number of student tickets sold. We know that a total of 1,160 tickets were sold, so:

x + y = 1160

We also know that the total amount collected was $2,600. The amount collected from adult tickets is $5 times the number of adult tickets sold, and the amount collected from student tickets is $1 times the number of student tickets sold. So:

5x + 1y = 2600

Now we have a system of two equations:

x + y = 1160

5x + y = 2600

We can solve for one of the variables in terms of the other, and substitute into the other equation to solve for the remaining variable. For example, we can solve the first equation for y:

y = 1160 - x

Now substitute this expression for y into the second equation:

5x + (1160 - x) = 2600

Simplifying and solving for x:

4x + 1160 = 2600

4x = 1440

x = 360

So 360 adult tickets were sold. To find the number of student tickets sold, we can use either equation. Let's use the first equation:

x + y = 1160

360 + y = 1160

y = 800

So 800 student tickets were sold.

Therefore, 360 adult tickets and 800 student tickets were sold.