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The shortest leg of a triangle is 4 cm less than the

longest leg. The leg in between them is 2 less than the
longest leg. The perimeter is 24. Find the length of
each leg.

1 Answer

4 votes

Explanation:

Let's start by assigning variables to the lengths of the legs of the triangle. Let x be the length of the longest leg, y be the length of the leg in between, and z be the length of the shortest leg.

From the problem statement, we can write two equations:

z = x - 4 (since the shortest leg is 4 cm less than the longest leg)

y = x - 2 (since the leg in between is 2 less than the longest leg)

We also know that the perimeter of the triangle is 24, so we can write a third equation:

x + y + z = 24

We can substitute the expressions for z and y in terms of x into the third equation to get:

x + (x - 2) + (x - 4) = 24

Simplifying this equation gives:

3x - 6 = 24

Adding 6 to both sides gives:

3x = 30

Dividing both sides by 3 gives:

x = 10

So the longest leg of the triangle is 10 cm. Using equations 1 and 2, we can find the lengths of the other two legs:

z = x - 4 = 10 - 4 = 6

y = x - 2 = 10 - 2 = 8

Therefore, the lengths of the three legs are 6 cm, 8 cm, and 10 cm.

answered
User Brian Noguchi
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