Question

Please explain how to do this

Answer 1

9514 1404 393

Answer:

1/2

Explanation:

The rules of exponents are helpful.

(a^b)^c = a^(bc)

a^-b = 1/a^b

__

`25^{(1)/(2)}*10^(-1)=\frac{(5^2)^{(1)/(2)}}{10^1}=\frac{5^{2\cdot(1)/(2)}}{10}\\\\=(5^1)/(10)=(5)/(10)=\boxed{(1)/(2)}`