asked 36.4k views
1 vote
a no. 10 steel rebar is tested in tension. by monitoring the load reading of the testing machine, it was found that the specimen yielded at a load of 41,600 lb and fractured at 48,300 lb. a. determine the tensile stresses at yield and at fracture. b. estimate how much increase in

asked
User Apascual
by
8.2k points

1 Answer

3 votes
a. To determine the tensile stresses at yield and at fracture, we need to know the cross-sectional area of the rebar. Let's assume that the cross-sectional area of the rebar is 0.785 square inches (which is the cross-sectional area for a No. 10 steel rebar according to some sources).

The tensile stress at yield is calculated as the yield load divided by the cross-sectional area:

Stress at yield = Yield load / Cross-sectional area = 41,600 lb / 0.785 sq in = 53,011 psi

The tensile stress at fracture is calculated as the fracture load divided by the cross-sectional area:

Stress at fracture = Fracture load / Cross-sectional area = 48,300 lb / 0.785 sq in = 61,508 psi

b. To estimate how much increase in load is required to cause a 1% deformation in the rebar, we need to know the original length of the rebar and the amount of deformation that corresponds to a 1% strain. Let's assume that the original length of the rebar is 12 feet (144 inches) and that a 1% strain corresponds to a deformation of 1.44 inches (which is the amount of deformation for a 12-foot length of rebar subjected to a 1% strain).

To calculate the increase in load required to cause a 1% deformation, we can use the following formula:

Increase in load = Cross-sectional area x Strain x Modulus of elasticity

where the modulus of elasticity for steel is typically around 29,000,000 psi.

Plugging in the values, we get:

Increase in load = 0.785 sq in x 1.44 in / 144 in x 29,000,000 psi = 625.4 lb

Therefore, an increase in load of about 625 lb would be required to cause a 1% deformation in the rebar.
answered
User Tamas Nagy
by
8.4k points