asked 28.0k views
1 vote
What is the equation of the line that passes through (5-2) and is perpendicular to y=-10+7

1 Answer

3 votes

Answer:

y = 1/10x - 5/2

Explanation:

I think you mean perpendicular to the line y = -10x + 7, and the point is (5, -2).

The slopes of perpendicular lines are negative reciprocals, so the perpendicular line has slope 1/10.

y = mx + b

y = (1/10)x + b

-2 = (1/10)(5) + b

-2 = 1/2 + b

-5/2 = b

y = 1/10x - 5/2

answered
User Hsarp
by
7.6k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.