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One leg of a right triangle is 7 inches longer than the other leg, and the hypotenuse is 35 inches. Find the lengths of the legs of the triangle.

The lengths of the legs are
Partially correct inches. (Separate with commas - order does not matter.)

asked
User Niqueco
by
7.8k points

2 Answers

2 votes

Answer:

Explanation:

answered
User Rastadrian
by
8.4k points
4 votes

Answer:

Explanation:

Let x be the length of the shorter leg of the triangle.

Then, the longer leg is 7 inches longer, which means its length is x + 7.

Using the Pythagorean theorem, we can write:

x^2 + (x + 7)^2 = 35^2 => x^2 + x^2 + 14x + 49 = 1225

Expanding the squares and simplifying, we get:

2x^2 + 14x - 576 = 0

We can solve for x by using the quadratic formula:

x = (-14 ± √(14^2 - 4(2)(-576))) / (2(2))

x = (-14 ± √(3968)) / 4

x ≈ 12.8 or x ≈ -17.8

Since x represents the length of a side of a triangle, it must be positive. Therefore, we take x ≈ 12.8 as the solution.

The lengths of the legs of the triangle are x ≈ 12.8 inches and x + 7 ≈ 19.8 inches.

So, the lengths of the legs of the triangle are approximately 12.8 inches and 19.8 inches.

answered
User Aurelije
by
8.7k points

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