Question

Help me, please.

Indicate the equation of the given line in standard form, using the equation box below.

The line containing the midpoints of the legs of right triangle ABC where A(–5, 5), B(1, 1), and C(3, 4) are the vertices.

Answer 1

4x + 6y = 23

Explanation:

xm = -5+3/2=-1

ym= 5+4/2 = 9/2

xm= 1+3/2=2

ym= 1+4/2=5/2

m= y2-y1/x2-x1

m= 5/2-9/2 / 2-(-1)

m=4/-2 /3

m=-2/3