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Answer:
a) 2n and 2n + 2
b) 2n - 1 and 2n + 1
Explanation:
All multiples of 2 are even, therefore 2n and 2n + 2 will always be even;
If all multiples if 2 are even, then 2n - 1 and 2n + 1 must always be odd
I think it would be the 4th one, 2n and 2n+1?