Question

Help me please i am running low on time and i can not work it out. My teacher will get mad at me if i get this question wrong i think it is easy but i can't do it

Answer 1

`x \approx 14.5 \text{ m}`

Explanation:

We can represent the base of the smaller right triangle with the variable y.

Solving for y using the Pythagorean Theorem:

`6^2 + y^2 = 11^2`

`y^2 = 11^2 - 6^2`

`y = √(121-36)`

`y = √(85)`

Using this y-value, we can solve for x by applying the Pythagorean Theorem to the larger right triangle.

Remember that the total base is length (4 +
`\sqrt{85`) meters.

`6^2 + (4 + √(85))^2 = x^2`

`x=\sqrt{137+8√(85)}`

Plugging this into a calculator, we get:

`\boxed{x \approx 14.5}`