Question

What is the Correct answer to these two questions??

Answer 1

well, atop is simply one-third divided by four, her, her brother and parents.

`\cfrac{1}{3}/ 4\implies \cfrac{1}{3}/ \cfrac{4}{1}\implies \cfrac{1}{3}\cdot \cfrac{1}{4}\implies \cfrac{1}{12}`

now for down below, let's firstly convert all mixed fractions to improper fractions and then proceed.

`\stackrel{mixed}{8(2)/(3)}\implies \cfrac{8\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{26}{3}}~\hfill \stackrel{mixed}{3(1)/(2)} \implies \cfrac{3\cdot 2+1}{2} \implies \stackrel{improper}{\cfrac{7}{2}} \\\\\\ \stackrel{mixed}{4(1)/(6)}\implies \cfrac{4\cdot 6+1}{6}\implies \stackrel{improper}{\cfrac{25}{6}}~\hfill \stackrel{mixed}{2(1)/(3)} \implies \cfrac{2\cdot 3+1}{3} \implies \stackrel{improper}{\cfrac{7}{3}} \\\\[-0.35em] ~\dotfill`

`\left( \cfrac{26}{3}-\cfrac{7}{2} \right)* \left( \cfrac{25}{6}+\cfrac{7}{3} \right)\implies \left( \cfrac{(2)26~~ - ~~(3)7}{\underset{\textit{using this LCD}}{6}} \right)* \left( \cfrac{(1)25~~ + ~~(2)7}{\underset{\textit{using this LCD}}{6}} \right)`

`\left( \cfrac{52-21}{6}\right)* \left( \cfrac{25+14}{6}\right)\implies \left( \cfrac{31}{6}\right)* \left( \cfrac{39}{6}\right)\implies \cfrac{1209}{36} \\\\\\ \cfrac{403}{12}\implies {\Large \begin{array}{llll} 33(7)/(12) \end{array}}`