Question

Could you please help. Thank you, also show me that solutions!

Answer 1

`~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \pounds 1153.76\\ P=\textit{original amount deposited}\dotfill & \pounds 1100\\ r=rate\to r\%\to (r)/(100)\\ t=years\dotfill &4 \end{cases}`

`1153.76 = 1100[1+((r)/(100))(4)] \implies \cfrac{1153.76}{1100}=1+\cfrac{r}{25}\implies \cfrac{1153.76}{1100}=\cfrac{25+r}{25} \\\\\\ 25\left( \cfrac{1153.76}{1100} \right)=25+r\implies \cfrac{1153.76}{44}=25+r \\\\\\ \cfrac{1153.76}{44}-25=r\implies \stackrel{ \% ~~ }{\boxed{1.22\approx r}}`