Question

How do you graph an equation if you had m= -1/3 and b = 2.

Answer 1

You first plot the point (0,2), then when the x-value of the graph increases by 3, decrease the y-value of the graph by 1, and when the x-value o the graph decreases by 3, increase the y-value of the graph by 1.

Explanation:

The equation would be
`y = -(1)/(3)x+2`. To graph it, you first need to find the y-intercept, which is the coordinate on the line when the x-value equals 0. If x = 0,
`y = -(1)/(3)x+2` would become
`y = 2` since anything multiplied by 0 would become 0. Now you've located the y-intercept, which is (0, 2). The slope of a line is the coefficient of the variable x. Since the slope is a negative number, the line will go downwards as it increases its x-value and goes upward as it decreases its x-value. A slope of
`-(1)/(3)` would mean that when the x-value increases by 3, the line's y-value will decrease by 1. And when the x-value decreases by 3, the line's y-value will increase by 1. An x-value increase of 6 would be a decrease of 2, and so on. Two other obvious points on the line would be (6,0) and (3, 1).