Question

Please help! what is the equation of a circle with radius 8 that has its center at the origin?

Answer 1

`x^2 + y^2 = 64`

Explanation:

The equation of a circle with radius "r" and center at the origin (0, 0) is:

`x^2 + y^2 = r^2`

In this case, the radius "r" is 8. Therefore, the equation of the circle is:

`x^2 + y^2 = 8^2`

Simplifying:

`x^2 + y^2 = 64`

So, the equation of the circle with radius 8 and center at the origin is:

`x^2 + y^2 = 64`