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find the equation of a straight line passing through the point (0,-1) which is perpendicular to the line y=-3/4x-3

asked
User Chink
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8.7k points

1 Answer

4 votes

Answer: y= 4/3x-1

Explanation:

The x of the equation is the slope and a perpendicular slope means that it is an opposite reciprocal, so we flip the numbers and the sign so the perpendicular slope is 4/3x. The b in y=mx+b is the y-intercept, the point (0,-1) is a y-intercept and the last number would be -1. So your equation would be y=4/3x-1

answered
User Rauli Rajande
by
7.9k points

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