Question

pls help!! What is an equation of the line that passes through the point (−6,−3) and is parallel to the line x−3y=9?

Answer 1

Explanation:

`x-3y=9`

`-3y=9-x`

`y=(1)/(3) x-3`

This is gradient intercept form with
`m=(1)/(3)` .

The required line is parallel and will also have gradient
`m=(1)/(3)` .

Substitute (-6,-3),
`m=(1)/(3)` into point gradient equation form:

`y-y_1=m(x-x_1)`

`y+3=(1)/(3) (x+6)`

`3y+9=x+6`

`x-3y=3`