Answer:
y = 10/3x + 130/3
Explanation:
To find where A is, we must find where C is. C is found when plugging in 0 in for y: 0 = -1/2 x + 5, so x = 10, and y = 0.
Now that we know the length of BC, we can find A.
Subtract 10 from the x value and add 5 to the y value of B to find A: (-10, 10).
Now, find the equation of the line between (-13, 0) and (-10, 10). Solve and get the equation of a line: y = 10/3x + 130/3
Hope this helps!