Answer:
2
Step-by-step explanation:
Seq. nth term, sum
The nth term of a sequence is n^2+ a
The 6th term of the sequence is 29
Find the sum of the first 4 terms
We are given that the nth term of the sequence is n^2 + a.
To find the value of 'a', we can use the fact that the 6th term of the sequence is 29.
Substituting n = 6 in the expression for the nth term, we get:
6^2 + a = 29
Simplifying this equation, we get:
a = 29 - 6^2
a = -7
So, the expression for the nth term of the sequence is:
n^2 - 7
Now, we need to find the sum of the first 4 terms of the sequence.
The first term of the sequence is given by substituting n = 1 in the expression for the nth term:
1^2 - 7 = -6
The second term of the sequence is given by substituting n = 2:
2^2 - 7 = -3
The third term of the sequence is given by substituting n = 3:
3^2 - 7 = 2
The fourth term of the sequence is given by substituting n = 4:
4^2 - 7 = 9
Therefore, the sum of the first 4 terms of the sequence is:
-6 + (-3) + 2 + 9 = 2