Question

300 ml of nitrogen react with 300 ml of hydrogen to form ammonia. N₂ + 3H₂ ---> 2NH3 What volume of ammonia will be formed, if the reaction gets over at the same temperature? a) 100 ml b) 200 ml c)300 ml d) 400 ml​

Answer 1

According to the balanced chemical equation for the reaction:

N₂ + 3H₂ → 2NH₃

1 volume of nitrogen (N₂) reacts with 3 volumes of hydrogen (H₂) to form 2 volumes of ammonia (NH₃) at the same temperature and pressure.

Therefore, if 300 ml of nitrogen (N₂) reacts with 300 ml of hydrogen (H₂), the limiting reactant will be hydrogen, since it is present in the smallest amount. To find the volume of ammonia (NH₃) formed, we can use the volume ratio from the balanced chemical equation:

1 volume of N₂ + 3 volumes of H₂ → 2 volumes of NH₃

Since we have 300 ml of H₂, which is equivalent to 3 volumes of H₂, the maximum volume of ammonia (NH₃) that can be formed is:

2 volumes of NH₃ = 300 ml of H₂ × (2 volumes of NH₃ / 3 volumes of H₂) = 200 ml

Therefore, the correct option is (b) 200 ml.