Find the center and radius of the circle whose equation is x^2+y^2+4y=32

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asked Aug 23, 2024 204k views

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Dirk Eschler · Answer 1 · 2024-08-29T07:29:54+0000

Answer:

center: (0, -2)

radius: 6

Explanation:

You have to "complete the square" this allows you to fold up the expressions and put the equation in a standard kinda of format where you can pick the center and radius right out of the equation.

see image.

Find the center and radius of the circle whose equation is x^2+y^2+4y=32-example-1

Find the center and radius of the circle whose equation is x^2+y^2+4y=32

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