Answer:
If f(x)=x^3, evaluate f(x+h)-f(x)÷h, Where h* 0. Use your result to find the derivative of f(x) with respect to x. Differentiate with respect to x (x²-3x+5)(2x-7) .Find with respect to x the derivative of sinx ÷1– cosx
Explanation:
We are given f(x) = x^3. We need to find the value of (f(x+h) - f(x))/h.
f(x+h) = (x+h)^3 = x^3 + 3x^2h + 3xh^2 + h^3
Therefore, (f(x+h) - f(x))/h = [x^3 + 3x^2h + 3xh^2 + h^3 - x^3]/h
= 3x^2 + 3xh + h^2
Taking the limit of the above expression as h approaches 0, we get:
lim(h→0) [(f(x+h) - f(x))/h] = 3x^2
Therefore, the derivative of f(x) = x^3 with respect to x is 3x^2.
Next, we need to differentiate (x^2-3x+5)(2x-7) with respect to x.
Using the product rule, we get:
d/dx [(x^2-3x+5)(2x-7)] = (2x-7)(2x-3) + (x^2-3x+5)(2)
Simplifying, we get:
d/dx [(x^2-3x+5)(2x-7)] = 4x^2 - 20x + 11
Therefore, the derivative of (x^2-3x+5)(2x-7) with respect to x is 4x^2 - 20x + 11.
Finally, we need to find the derivative of sin(x)/(1-cos(x)) with respect to x.
Using the quotient rule, we get:
d/dx [sin(x)/(1-cos(x))] = [(1-cos(x))cos(x) - sin(x)(sin(x))]/(1-cos(x))^2
Simplifying, we get:
d/dx [sin(x)/(1-cos(x))] = cosec(x/2)^2
Therefore, the derivative of sin(x)/(1-cos(x)) with respect to x is cosec(x/2)^2.