Solve the following quadratic-like equation. y^(1)/(2) -6y^(1)/(4) +8=0

Question

Solve the following quadratic-like equation.


`y^(1)/(2) -6y^(1)/(4) +8=0`

Answer 1

Explanation:

given quadratic equation is

simplification,

by using,

`y^(1)/(2) -6y^(1)/(4) +8=0</p><p> \\ y^(1)/(2) -6y^(1)/(4) = - 8 \\ </p><p>`

`square`

`\\ {(y^(1)/(2) -6y^(1)/(4))}^(2) = {(- 8)}^(2)`

`y + 36 {y}^{ (1)/(2)} \:`