Question

1. What volume of hydrogen gas at STP is produced from the

reaction of 50.0g of Mg and 75.0 grams of HCl? How much
of the excess reagent is left over (in grams)?

Answer 1

1.03 mol of dihydrogen gas will evolve, with a volume slightly over 22.4 dm3 at ST P. Explanation: Moles of magnesium: 50.0 ⋅ g 24.31 ⋅ g ⋅ mol−1 = 2.06 mol Moles of hydrogen chloride gas: 75.0 ⋅ g 36.2⋅ g ⋅ mol−1 = 2.07 mol

Step-by-step explanation:

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