Question

TS is the height of a building. PQR is a pole in front of the building. QT is a horizontal cable that supports the pole to the building. Find the height of the pole?​

Answer 1

The answer is 65.75

Explanation:

Since tq is perpendicular to PR then qtsr becomes square

Then

`qr = 30 \: \: \: \: \: and \: qt = 30 \\`

Since the triangle pqt is right angled

Then

`pq = qt \tan(50) = 30 * \tan(50 ) = 35.75`

Then the height of the pole is equal to

`pq + qr = 35.75 + 30 = 65.75`