Question

Solve for ΔX in the equation Vf²=Vo²+2aΔX.

Answer 1

To find ∆X in the equation, rearrange it to ∆X = (Vf² - Vo²) / (2a) and substitute the known values for Vo, Vf, and a.

Step-by-step explanation:

To solve for ∆X in the equation Vf² = Vo² + 2a∆X, follow these steps:

1. Identify the known variables: initial velocity (Vo), final velocity (Vf), and acceleration (a).
2. Set xo (initial position) to zero if it is not given, which seems to be the case in this question.
3. Rearrange the equation to solve for ∆X: ∆X = (Vf² - Vo²) / (2a).
4. Substitute the known values into the equation and calculate ∆X.

For instance, if Vo = 30.0 m/s, Vf is 0 (the object has come to a stop), and a is -7.00 m/s² (deceleration), the displacement ∆X is calculated as follows:

∆X = (0 - (30.0 m/s)²) / (2 * -7.00 m/s²) = (0 - 900) / (-14) = 64.29 meters