The x-intercepts of the function are (-√5, 0) and (√5, 0)
Given the equation of the expression
f(x) = 5x^2 - 25x/x
The x-intercept is the point where f(x) = 0
Equating f(x) = 0, we will have:
5x^2 - 25x/x = 0
5x^2 - 25 = 0
Add 25 to both sides
5x^2 = 0 + 25
5x^2 = 25
x^2 = 25/5
x^2 = 5
x = ±√5
Hence the x-intercepts of the function are (-√5, 0) and (√5, 0)