Final answer:
When 10.26 grams of nitrogen and 10.21 grams of hydrogen react together, 0.7326 moles of ammonia are produced.
Step-by-step explanation:
According to the balanced equation, one mole of nitrogen reacts with three moles of hydrogen to produce two moles of ammonia. To determine how many moles of ammonia are produced when 10.26 grams of nitrogen and 10.21 grams of hydrogen react together, we need to convert the given masses to moles using the molar mass of each element.
Nitrogen has a molar mass of 28.02 g/mol, so 10.26 grams of nitrogen is equal to 10.26 g / 28.02 g/mol = 0.3663 moles of nitrogen.
Hydrogen has a molar mass of 2.02 g/mol, so 10.21 grams of hydrogen is equal to 10.21 g / 2.02 g/mol = 5.0554 moles of hydrogen.
Now, we can use the mole ratio from the balanced equation to determine the number of moles of ammonia produced. Since the ratio is 1:2 in the equation (1 mole nitrogen reacts to produce 2 moles of ammonia), we multiply the moles of nitrogen by the ratio: 0.3663 moles of nitrogen x 2 moles of ammonia / 1 mole of nitrogen = 0.7326 moles of ammonia.
Therefore, when 10.26 grams of nitrogen and 10.21 grams of hydrogen react together, 0.7326 moles of ammonia are produced.