Final answer:
The PRF of a transducer is independent of its frequency, making the statement false. PRF is related to imaging depth, not to the frequency of the transducer. Thus, a 6 MHz transducer does not inherently have a greater PRF than a 3 MHz transducer.
Step-by-step explanation:
The statement "The PRF of the 6 MHz transducer is greater than the PRF of the 3 MHz transducer" can be addressed by understanding that Pulse Repetition Frequency (PRF) is independent of the transducer frequency. PRF is determined by factors like the imaging depth, as it is the number of pulses that are sent out per second. It is not necessarily connected to whether the transducer is a 3 MHz or a 6 MHz. In general, a higher frequency transducer, like 6 MHz, is used for more detailed images of superficial structures, whereas a lower frequency transducer, like 3 MHz, is used for deeper penetration as it has a longer wavelength. Thus, the statement does not hold true by default and the correct answer to the question is b. False.
Here are some related concepts to assist with other questions on the topic of waves and ultrasound:
- Waves can superimpose regardless of whether their frequencies are the same or different, resulting in phenomena like constructive and destructive interference.
- The Doppler effect occurs with all types of waves, including sound, light, and water waves, whenever there is relative motion between the source of waves and the observer.
- The amplitude of a wave can be affected by the superposition of another wave, depending on their relative phase and alignment, not just when they are precisely aligned.