Question

Al2(SO4)3 + 6NaOH = 2Al(OH)3 + 3Na2SO4

Aluminum sulfate reacts with sodium hydroxide and produces 17 moles of sodium sulfate. How many moles of aluminum hydroxide are also produced?

Please help

Answer 1

To determine the number of moles of aluminum hydroxide produced, we can use the mole ratio between aluminum sulfate and aluminum hydroxide we get approximately 11.33 moles of aluminum hydroxide are produced.

Step-by-step explanation:

To determine the number of moles of aluminum hydroxide produced, we can use the mole ratio between aluminum sulfate and aluminum hydroxide. According to the balanced equation, for every 1 mole of aluminum sulfate (Al2(SO4)3) that reacts, 2 moles of aluminum hydroxide (Al(OH)3) are produced.

Since the balanced equation states that 2 moles of aluminum hydroxide are produced for every 3 moles of sodium sulfate, and we know that the reaction produces 17 moles of sodium sulfate, we can find the number of moles of aluminum hydroxide produced by setting up a proportion:

(2 mol Al(OH)3 / 3 mol Na2SO4) = (x mol Al(OH)3 / 17 mol Na2SO4)

Solving for x, we find that x = 11.33 moles.

Therefore, approximately 11.33 moles of aluminum hydroxide are produced.