Question

Can anyone solve this​

Answer 1

see explanation

Explanation:

Consider the left side

`(1+sinA)/(cosA)` +
`(cosA)/(1+sinA)` ← combine into a single fraction

=
`((1+sinA)^2+cos^2A)/(cosA(1+sinA))` ← expand and simplify numerator

=
`(1+2sinA+sin^2A+cos^2A)/(cosA(1+sinA))` [ sin²A + cos²A = 1 ]

=
`(1+2sinA+1)/(cosA(1+sinA))`

=
`(2+2sinA)/(cosA(1+sinA))` ← factor out 2 on the numerator

=
`(2(1+sinA))/(cosA(1+sinA))` ← cancel (1 + sinA) on numerator/ denominator

=
`(2)/(cosA)`

= 2secA = right side, thus verified

Answer 2

Step-by-step explanation:=(1+sinA)2+cos2A/cosA(1+sinA)

=1+sin2 A+2sin A+cos2 A/cos A(1+sin A)

=1+2sin A+1/cos A(1+sin A)

=2(1+sin A)/cos A(1+ sin A)

=2sec A