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David measured a line to be 13.5 inches long. If the actual length of the line is 16.6 inches, then what was the percent error of the measurement, to the nearest tenth of a perc…

David measured a line to be 13.5 inches long. If the actual length of the line is 16.6 inches, then what was the percent error of the measurement, to the nearest tenth of a perc…
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David measured a line to be 13.5 inches long. If the actual length of the line is 16.6 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?

asked
User Christofer Eliasson
by
8.0k points

2 Answers

3 votes

Answer:-23

Explanation:

answered
User JonnyLitt
by
8.2k points
10 votes

Answer:

18.67

Explanation:

(l2-l1)/l2 * 100%

where l2=16.6

l1=13.5

answered
User Mandee
by
7.8k points
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