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Find the value of the expression :


{x}^(2) + 2xy + {y}^(2)



y = (3 + i )/(i) \\ x = 2 + 3i


1 Answer

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Answer: x² + 2xy + y² = 9

x² + 2xy + y² = (x + y)²

with x = 2 + 3i and y =
(3+i)/(i), we have:


(x + y)^(2)=(2+3i+(3+i)/(i))^(2)\\\\=((2i+3i^(2)+3+i )/(i))^(2)\\\\=((3i-3+3)/(i))^(2) \\\\=((3i)/(i))^(2)\\\\=3^(2)=9

Explanation:

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