Question

Bruce's bedroom is 5 meters long and 5 meters wide. Starting at the far left corner, Bruce

walks down the length, across the width, and then diagonally back to the far left corner. How
far does Bruce walk? If necessary, round to the nearest tenth.
meters

Answer 1

Explanation:

Using Pythagoras theorem,

diagonal distance= sqrt(5^2+5^2)

=5*sqrt(2)

Total distance = 5+5+5*sqrt(2)

= 5(1+1+sqrt(2))

=5(2+1.44)

=5*3.44

=17.2m