How much solute will you need to prepare 170mL of 2.5% (M/v) KCL solution

Question

asked Dec 14, 2024 192k views

1 Answer

Alec Sibilia · Answer 1 · 2024-12-20T11:17:00+0000

You will need 4.25 grams of KCl to prepare 170 mL of a 2.5% (M/v) KCl solution.

To calculate how much solute is needed to prepare 170 mL of a 2.5% (M/v) KCl solution, we use the following formula:

Mass of solute (g) = Volume of solution (mL) × Percentage concentration (M/v) / 100

Plugging in the values:

Mass of solute (g) = 170 mL × 2.5% / 100

= 4.25 g

Therefore, you will need 4.25 grams of KCl to prepare 170 mL of a 2.5% (M/v) KCl solution.